1/2 (ps*dvsx2/dx – pf*dvfx2/dx)=-3k/[(2k+1)(1-q)de]*1/2*(ps*vsx2-pf*vfx2)-1/(2k+1)

can solve to=>   1/2 (ps*vsx2- pf*dvfx2)=(1-q)de/(3k)[exp(-3k/((2k+1)(1-q)de)*x)-1], right?

Is this expectance or exponential?

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