A store selling newspapers orders only x=4 of a certain newspaper because the manager does not get many calls for that publication. If the number of requests per day follows a Poisson distribution with mean 3.a) What is the expected value of the number sold?b) How many should the manager order so the chance of running out is less than 0.05?

Poisson’s distribution,e− μ μ xPr( x) =x!(a). For a Poisson’s distribution, expected number of success is equal to the mean of the distribution.Thus,E ( x) = μ⇒ E ( x) = 3…