In a random sample of 60 refrigerators, the mean repair cost was 147.00 and the population standard deviation is 16. Construct a 95 % confidence…

In a random sample of 60 ​refrigerators, the mean repair cost was 147.00 and the population standard deviation is 16.30. Construct a 95​%

confidence interval for the population mean repair cost. Interpret the results. Construct a 95​% confidence interval for the population mean repair cost.

The 95​% confidence interval is—–,—-.,.

​(Round to two decimal places as​ needed.)

Interpret you results. Choose the correct answer below.

A.

With 95​% ​confidence, it can be said that the confidence interval contains the sample mean repair cost.

B.

The confidence interval contains 95​% of the mean repair costs.

C.

With 95​% ​confidence, it can be said that the confidence interval contains the true mean repair cost.

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